The correct answer is A . The exhibit shows two adapters learned on the same wired port: one appears as a rogue/unknown host, and the other is associated with the Lab Hosts rule. The port is in both Role-Based Access and Forced Registration . FortiNAC-F state-based control takes precedence over policy-based provisioning, and the study guide states that when a rogue host connects to a port in the Forced Registration group, FortiNAC-F isolates that host by moving it into the registration captive network. The guide also explains that the Isolation network can be used as a single network for abnormal host states while still presenting state-specific portal pages.
Because this is a wired switch port using VLAN-based control, FortiNAC-F cannot put one host on the production VLAN and the other host on the isolation portal VLAN at the same time on the same access port.
The VLAN change applies to the port, not independently to each MAC address behind that port. Therefore, the presence of the rogue host on a Forced Registration port causes the port to be provisioned to the isolation network. Option B is technically unrealistic for this access-port scenario. Option C is wrong because two MAC addresses alone do not make the port an uplink; FortiNAC-F uses uplink logic for infrastructure-device MACs, manually marked uplinks, or a threshold such as more than 20 MAC addresses. Option D is unrelated because Access Point Management is not triggered by learning two wired hosts on a port.